Thursday, June 11, 2015

AC Circuit-LRC Day


This is the impedance equation for circuits that has all the bells and whistles. It has factors for resistors, inductors, and capacitors.


These are some of the equations that were used to calculate different aspects of the entire work.
The main equation is Z= Sqrt(R^2*(XL-XC)^2). Its a very simple equation that gets simpler when you take some of the aspects out


This is what we are suppose to fine with the experiential at we are about to do. We already have the frequency and the resistor. We have Z(theoretical)

This is the results we got after connecting everything together. It was a very simple processes


And we were able to find everything with less then a 25 percent error for both the cases. We did run into a little calculation snafu when we disagree how we should proceed with things.

AC circuit-RC Day

This is the part of the hand out we will be going over today.



This is a beautiful graph of what the Voltage vs Time and Current vs Time. Also the third graph is Voltage vs Current. Again this looks beautiful.


This is the setup for the lab we did this day. We are only using the capacitor and the resistor so its a RC circuit. 


Here is the equation we use to calculate the Irms of the graph. We also used the values from the graph to verify what we got.


EMF


This day was a subset of what we did in the previous day which was magnetic fields. We used ActivPhysics to answer 13 questions. That answers are on the board, but it doesn't really explain anything unless you have the questions with it. In the end we verified some aspects of an induced EMF


This was the sliding pipe prediction that we had had before Mason little exert to the class; which is below.







This is a good Voltage vs Time with Current vs Time graph. As one could see voltage is constant while current

Over time the time constant flattens out. Depending on curtain factors it may flatten out faster or slower but it will go to the same constants  

Tuesday, March 31, 2015

Vpython Lab


This is what the original code would have looked like if we did not change the code that was given to use my Prof. Mason. It was very simple in practice. The code that made this image is below.

This code is what we made with some help from Mason during class. We changed the direction and the size of each arrow to best represent what we had.

from visual import *

## CONSTANTS
k = 9e9   ## OneOverFourPiEpsilonZero
q1 = 1.6e-19

## OBJECTS
particle = sphere(pos=vector(1e-10, 0, 0), radius = 2e-11, color=color.red)
xaxis = cylinder(pos=(-5e-10,0,0), axis=vector(10e-10,0,0),radius=.2e-11)
yaxis = cylinder(pos=(0,-5e-10,0), axis=vector(0,10e-10,0),radius=.2e-11)
zaxis = cylinder(pos=(0,0,-5e-10), axis=vector(0,0,10e-10),radius=.2e-11)

## the position of the arrow is the observation location:
Earrow1 = arrow(pos=vector(3.1e-10,-2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)
Earrow2 = arrow(pos=vector(3.1e-10,2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)
Earrow3 = arrow(pos=vector(-1.1e-10,-2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)
Earrow4 = arrow(pos=vector(-1.1e-10,2.1e-10,0), axis = vector(1e-10,0,0), color=color.orange)
Earrow5 = arrow(pos=vector(1e-10,0,3e-10), axis = vector(1e-10,0,0), color=color.orange)
Earrow6 = arrow(pos=vector(1e-10,0,-3e-10), axis = vector(1e-10,0,0), color=color.orange)
## CALCULATIONS
R1=Earrow1.pos-particle.pos
R2=Earrow2.pos-particle.pos
R3=Earrow3.pos-particle.pos
R4=Earrow4.pos-particle.pos
R5=Earrow5.pos-particle.pos
R6=Earrow6.pos-particle.pos

Ef1=((k*q1)/(mag(R1)**3))
Ef2=((k*q1)/(mag(R2)**3))
Ef3=((k*q1)/(mag(R3)**3))
Ef4=((k*q1)/(mag(R4)**3))
Ef5=((k*q1)/(mag(R5)**3))
Ef6=((k*q1)/(mag(R6)**3))


## write instructions below to tell the computer how to calculate the correct
## electric field E1 at the observation location (the position of Earrow1):

## change the axis of Earrow1 to point in the direction of the electric field at that location
## and scale it so it looks reasonable

scalefactor= 1e-20
Earrow1.axis= Ef1*R1*scalefactor
Earrow2.axis= Ef2*R2*scalefactor
Earrow3.axis= Ef3*R3*scalefactor
Earrow4.axis= Ef4*R4*scalefactor
Earrow5.axis= Ef5*R5*scalefactor
Earrow6.axis= Ef6*R6*scalefactor

print "Ef1: ", Ef1
print "Ef2: ", Ef2
print "Ef3: ", Ef3
print "Ef4: ", Ef4
print "Ef5: ", Ef5
print "Ef6: ", Ef6

## additional observation locations; do the same thing for each one



The output is such.



Our next time we use Vpython we had a cool picture both in 2D and 3D but we dont have the picture of it right now. However, i do have a prediction of what the forces around the two charges might look like in a 2D space.


 Here is the code for it. We were just representing the motion that a small positive charge would move if it was near a charge. The image is really cool. Just found the picture. It is at the bottom
from __future__ import division from visual import * ## constants k = 9e9 # stands for One Over Four Pi Epsilon-Zero qe = 1.6e-19 # proton charge s = 4e-11 # charge separation R = 3e-10 # display Enet on a circle of radius R V = 2e-10 scalefactor = 1e-20 # for scaling arrows to represent electric field ## objects ## Represent the two charges of the dipole by red and blue spheres: plus = sphere(pos=vector(s/2,0,0), radius=1e-11, color=color.red) qplus = qe # charge of positive particle neg = sphere(pos=vector(-s/2,0,0), radius=1e-11, color=color.blue) qneg = -qplus # charge of negative particle ## calculations theta = 0 while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=R*vector(cos(theta),sin(theta),0), axis=vector(1e-10,0,0), color=color.orange) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/12 theta = 0 while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=R*vector(cos(theta),0,sin(theta)), axis=vector(1e-10,0,0), color=color.orange) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/12 theta = 0 while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=R*vector(0,cos(theta),sin(theta)), axis=vector(1e-10,0,0), color=color.orange) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/12 theta = 0 scalefactor= 1*(10**(-20.5)) while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=V*vector(cos(theta),sin(theta),0), axis=vector(1e-10,0,0), color=color.red) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/12 theta = 0 while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=V*vector(cos(theta),0,sin(theta)), axis=vector(1e-10,0,0), color=color.red) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/12 theta = 0 while theta < 2*pi: rate(50) # tell computer to go through loop slowly ## Calculate observation location (tail of arrow) using current value of theta: Earrow1 = arrow(pos=V*vector(0,cos(theta),sin(theta)), axis=vector(1e-10,0,0), color=color.red) R1= Earrow1.pos-plus.pos R2= Earrow1.pos-neg.pos Ef1=((k*qplus)/(mag(R1)**3)) Ef2=((k*qneg)/(mag(R2)**3)) Earrow1.axis= ((Ef1*R1)+(Ef2*R2))*scalefactor print "Ef1: ", Ef1 ## write instructions below to tell the computer how to calculate the correct ## net electric field Enet at the observation location (the position of Earrow): ## change the axis of Earrow to point in the direction of the electric field at that location ## and scale it so it looks reasonable ## Assign a new value to theta theta = theta + pi/
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